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Compare a string with the string.
template< typename T> constexpr int compare( size_type pos1, size_type count1, const T& t, size_type pos2, size_type count2 = npos) const;
Let sub1 be substr(pos1, count1),
sub2 be string_view_type(t).substr(pos2, count2),
and comp be traits_type::compare(sub1.data(), sub2.data(), std::min(sub1.size(), sub2.size()).
If comp !=
0, then the result is comp. Otherwise, the result is 0 if sub1.size() == sub2.size(),
-1
if sub1.size() < sub2.size(), and 1
otherwise.
Linear.
Strong guarantee.
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Type |
Description |
|---|---|
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|
The type of the object to convert. |
std::is_convertible<const T&, string_view>::value && !std::is_convertible<const T&, const_pointer>::value.
The result of lexicographically comparing sub1
and sub2.
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Name |
Description |
|---|---|
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|
The index at which to begin the substring in the string. |
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The length of the substring in the string. |
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The string to compare. |
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The index at which to begin the substring in the string view. |
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The length of the substring in the string view. |